w^2+11w=63

Solution for w^2+11w=63 equation:

w^2+11w=63

We move all terms to the left:

w^2+11w-(63)=0

a = 1; b = 11; c = -63;
Δ = b2-4ac
Δ = 112-4·1·(-63)
Δ = 373
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{373}}{2*1}=\frac{-11-\sqrt{373}}{2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{373}}{2*1}=\frac{-11+\sqrt{373}}{2}
$